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Improve divergence checking for loops #51053
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,45 @@ | ||
// Copyright 2018 The Rust Project Developers. See the COPYRIGHT | ||
// file at the top-level directory of this distribution and at | ||
// http://rust-lang.org/COPYRIGHT. | ||
// | ||
// Licensed under the Apache License, Version 2.0 <LICENSE-APACHE or | ||
// http://www.apache.org/licenses/LICENSE-2.0> or the MIT license | ||
// <LICENSE-MIT or http://opensource.org/licenses/MIT>, at your | ||
// option. This file may not be copied, modified, or distributed | ||
// except according to those terms. | ||
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#![feature(never_type)] | ||
#![allow(unreachable_code)] | ||
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fn main() { | ||
// The `if false` expressions are simply to | ||
// make sure we don't avoid checking everything | ||
// simply because a few expressions are unreachable. | ||
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if false { | ||
let _: ! = { | ||
loop { return } // ok | ||
}; | ||
} | ||
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if false { | ||
let _: ! = { | ||
loop { return; break } // ok | ||
}; | ||
} | ||
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if false { | ||
let _: ! = { | ||
// Here, the break (implicitly carrying the value `()`) | ||
// occurs before the return, so it doesn't have the type | ||
// `!` and should thus fail to type check. | ||
loop { return break } //~ ERROR mismatched types | ||
}; | ||
} | ||
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if false { | ||
let _: ! = { | ||
loop { break } //~ ERROR mismatched types | ||
}; | ||
} | ||
} |
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Original file line number | Diff line number | Diff line change |
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error[E0308]: mismatched types | ||
--> $DIR/loop-return-break.rs:36:27 | ||
| | ||
LL | loop { return break } //~ ERROR mismatched types | ||
| ^^^^^ expected (), found ! | ||
| | ||
= note: expected type `()` | ||
found type `!` | ||
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error[E0308]: mismatched types | ||
--> $DIR/loop-return-break.rs:42:20 | ||
| | ||
LL | loop { break } //~ ERROR mismatched types | ||
| ^^^^^ expected (), found ! | ||
| | ||
= note: expected type `()` | ||
found type `!` | ||
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error: aborting due to 2 previous errors | ||
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For more information about this error, try `rustc --explain E0308`. |
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Hmm, I think if we are going to "do this", we might want to consider "doing it right". In particular, the value of the diverges flag on entry to an expression does not indicate if "all prior points in the CFG diverged" but rather if some preceding subexpression within the parent diverged.
This means that while this test works now:
I expect that this one will fail, right?
Put another way, I am wary of adding rules that try to use the existing divergence mechanism to figure out if prior code had diverged.
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Yes, that's correct.