Skip to content

Added solution to Leetcode Question - 7 | Reverse Integer #93

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Merged
merged 3 commits into from
Oct 24, 2021
Merged
Show file tree
Hide file tree
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
35 changes: 35 additions & 0 deletions 0007/README.md
Original file line number Diff line number Diff line change
@@ -0,0 +1,35 @@
# Reverse Integer

Given a signed 32-bit integer ```x```, return ```x``` with its digits reversed. If reversing ```x``` causes the value to go outside the signed 32-bit integer range ```[-231, 231 - 1]```, then return ```0```.

**Assume the environment does not allow you to store 64-bit integers (signed or unsigned).**


## Examples

* Example 1
```
Input: x = 123
Output: 321
```

* Example 2
```
Input: x = -123
Output: -321
```

* Example 3
```
Input: x = 120
Output: 21
```

* Example 4
```
Input: x = 0
Output: 0
```

## Constraints
* -231 <= x <= 231 - 1
5 changes: 5 additions & 0 deletions 0007/reverse_integer.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,5 @@
class Solution:
def reverse(self, x):
s = str(x)
res = (int('-' + s[1:][::-1]) if s[0] == '-' else int(s[::-1]))
return (res if -2147483648 <= res <= 2147483647 else 0)